Two particles vibrating simple harmonically with amplitude A and frequency co along the same straight line. They pass one another when going in opposite direction. Each time when they cross are at a distance 0.707A. What is the phase difference between them?

Let the equation of motion of two particles be, 



where,

ϕ is the phase difference between two particles.

Each time the particles cross at a distance 0.707A.

Therefore, 

          0.707A=A sin 

and    0.707A=A sin(wt+


       0.707=sin and, 

          0.707= sn 

Now,

     sin(=sin(=sin 

     

Since,  

 

We can see that ϕ = 0 is not possible.

Therefore the phase difference between two particles is 90°. 

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An ideal gas is enclosed in a horizontal cylinder of area of cross-section A fitted with an airtight and frictionless piston of mass M. The piston is in equilibrium with atmospheric pressure P. The volume of gas enclosed in the cylinder is V. The cylinder is slightly displaced from equilibrium position and released. Show that the motion of piston is simple harmonic motion and find the time period of oscillation. Assume that the system is completely isolated from surrounding.

The system is as shown in figure. Let the piston be displaced by y towards left. Let dV be the decrease in volume and dP be the increase of pressure.


The system is as shown in figure. Let the piston be displaced by y to

Since the system is isolated from surrounding, therefore the change in pressure and volume is according to adiabatic conditions. Thus the equation of state can be written as

space space space space space space PV to the power of straight y equals space constant
or space space space space PγV to the power of straight y minus 1 end exponent dV plus straight V to the power of straight y dP equals 0
or space space space space space dP equals negative yPdV over straight V space space space space space space space space space space space space.... left parenthesis 1 right parenthesis

The equation (1) gives the change in pressure of gas when the volume of gas is changed by dV. Here change in volume of gas when the piston is displaced by y is Ay. Thus

dP equals negative yPA over straight V straight y

Force on piston is,

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The acceleration of piston is,

              straight a equals straight F over straight M equals negative yPA squared over MV straight y equals negative straight omega squared straight y

It is clear from the above equation that the acceleration is proportional to displacement and directed towards mean position, therefore the motion of piston is simple harmonic motion. The time period of oscillation is,

straight T equals 2 straight pi square root of 1 over straight omega squared end root equals 2 straight pi square root of MV over yPA squared end root

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Show that motion of body dropped in a tunnel dug along the diameter of the earth is simple harmonic motion. Find the time period of motion.

Let the earth be a homogenous sphere of radius R and density ρ. Let the bore be dug along the diameter of the earth.


Let the earth be a homogenous sphere of radius R and density ρ. Let

The acceleration due to gravity at point P at a distance y from the centre of the earth is

straight a equals 4 over 3 πGpy equals 4 over 3 πGρ straight R over straight R straight y equals straight g over straight R straight y

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Therefore the motion is simple harmonic motion.


straight omega squared equals straight g over straight R
therefore space space space straight T equals 2 straight pi square root of 1 over straight omega squared end root equals 2 straight pi square root of straight R over straight g end root

Substituting R and g, we get,

T equals 2 pi square root of fraction numerator 6.4 cross times 10 to the power of 6 over denominator 9.8 end fraction end root equals 5079 s
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What is free oscillator? Write the differential equation for free oscillator.

When an oscillator is displaced from equilibrium position, it executes simple harmonic motion. The time period of its oscillation depends upon its inertia factor and elastic factor. If the amplitude of oscillations remains constant in the absence of any external source of energy, then the oscillations are called free oscillations and oscillator is called free oscillator. The frequency with which the oscillator oscillates is called natural frequency.

The differential equation of free oscillator is,

fraction numerator straight d squared straight y over denominator dt squared end fraction plus straight k over straight m straight y equals 0

The solution of the above equation is,


straight y equals Asin left parenthesis ωt plus straight ϕ right parenthesis

The energy of oscilation is,

straight E equals 1 half mω squared space straight A squared

As the amplitude of free oscillations is constant, therefore energy of oscillation is also constant. The energy-time and displacement-time curve for free oscillation is as shown in figure.


When an oscillator is displaced from equilibrium position, it execute


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What is damped oscillation. Write the differential equation for damped oscillations. Obtain an expression for the displacement in the case of damped oscillatory motion. Discuss how the amplitude of oscillation changes with time?


When an oscillator oscillates in resistive medium, the energy of oscillation is consequently decreased. The amplitude of such an oscillator decreases with time and ultimately the oscillations die out. This type of oscillator is called damped oscillator.


When an oscillator oscillates in resistive medium, the energy of osci

Let us consider a loaded spring oscillating in vertical direction in a resistive media. Let m be the mass of load and k be the spring constant. The load is displaced from equilibrium position and let at any instant, y be the displacement from equilibrium position and v is the velocity of load. The different forces acting on load are:

(i) the restoring force which is proportional to displacement and directed towards equilibrium position, i.e.

F1= – ky

(ii) resistive force of medium which is proportional to velocity and opposite to the direction of velocity, i.e.

F2 = –bv The net force acting on the load is,

F = Fx1 + F2 = – ky –bv

Therefore the equation of motion of load is,

      straight m fraction numerator straight d squared straight y over denominator dt squared space end fraction equals negative ky minus straight b dy over dt
or space straight m fraction numerator straight d squared straight y over denominator dt squared space end fraction plus straight b dy over dt plus ky equals 0
or space space fraction numerator straight d squared straight y over denominator dt squared end fraction plus straight b over straight m dy over dt plus straight k over straight m straight y equals 0

This is the required differntial equation of motion of damped oscillations. The solution of the equation is,

straight y equals straight A subscript 0 straight e to the power of fraction numerator straight b over denominator 2 straight m end fraction straight i end exponent cos open square brackets open parentheses square root of straight k over straight m minus fraction numerator straight b squared over denominator 4 straight m squared end fraction end root close parentheses straight r plus straight ϕ close square brackets
Comparing it with space space straight y equals Acos left parenthesis ωt plus straight ϕ right parenthesis, we get,

straight A equals straight A subscript 0 straight e to the power of fraction numerator straight h over denominator 2 straight m end fraction straight i end exponent                                      .....(1)

and space space space space straight omega equals square root of straight k over straight m minus fraction numerator straight b squared over denominator 4 straight m squared end fraction end root equals square root of straight omega subscript 0 squared minus fraction numerator straight b squared over denominator 4 straight m squared end fraction end root space space space...... left parenthesis 2 right parenthesis

Equation (1) gives the amplitude of oscillation, which decreases exponentially with time.


When an oscillator oscillates in resistive medium, the energy of osci

Equation (2) gives the frequency of oscillation which is less than the natural frequency of oscillation ω0.

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